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Даныточки \(K, M, P, O\) . Представьвектор \(\overrightarrow{KM}\) ввидеалгебраическойсуммывекторов:

а) \(\overrightarrow{MO}, \overrightarrow{KP}, \overrightarrow{OP}\) ;

б) \(\overrightarrow{PM}, \overrightarrow{OK}, \overrightarrow{PO}\) .

• \(\overrightarrow{OM}\)
• \(\overrightarrow{OP}\)
• \(\overrightarrow{MO}\)
• \(\overrightarrow{OP}\)
• \(\overrightarrow{MO}\)
• \(\overrightarrow{KP}\)
• \(\overrightarrow{OP}\)
• \(\overrightarrow{PM}\)
• \(\overrightarrow{OK}\)
• \(\overrightarrow{PO}\)
• \(\overrightarrow{PM}\)
• \(\overrightarrow{MK}\)

Решение.

а)Используяравенства \(\overrightarrow{KM}=\overrightarrow{KP}+\overrightarrow{PO}+\) [ ], \(\overrightarrow{PO}=-\) [ ], \(\overrightarrow{OM}=-\) [ ], получаем \(\overrightarrow{KM}=\) [ ] \(-\) [ ] \(-\) [ ].

б) \(\overrightarrow{KM}=\overrightarrow{KO}+\) [ ] \(+\) [ ] \(=-\) [ ] \(-\) [ ] \(+\) [ ].

• \(+\overrightarrow{KP}\)
• \(-\overrightarrow{OP}\)
• \(-\overrightarrow{MO}\)
• \(-\overrightarrow{OK}\)
• \(-\overrightarrow{PO}\)
• \(+\overrightarrow{PM}\)
• \(+\overrightarrow{OK}\)
• \(-\overrightarrow{PM}\)
• \(-\overrightarrow{OM}\)

Ответ:

а) \(\overrightarrow{KM}=\) [ ][ ][ ];

б) \(\overrightarrow{KM}=\) [ ][ ][ ].