Задание

Заполни пропуски

Реши неравенство \(-2\lt \dfrac{1-2x}{3}-2\lt 0\) .

Решение.

[ ][ \(\gt \) | \(\lt \) | \(=\) | \(\geqslant \) | \(\leqslant \) ] \(\dfrac{1-2x}{3}\) [ \(\gt \) | \(\lt \) | \(=\) | \(\geqslant \) | \(\leqslant \) ][ ];

[ ][ \(\gt \) | \(\lt \) | \(=\) | \(\geqslant \) | \(\leqslant \) ] \(1-2x\) [ \(\gt \) | \(\lt \) | \(=\) | \(\geqslant \) | \(\leqslant \) ][ ];

[ ][ \(\gt \) | \(\lt \) | \(=\) | \(\geqslant \) | \(\leqslant \) ] \(-2x\) [ \(\gt \) | \(\lt \) | \(=\) | \(\geqslant \) | \(\leqslant \) ][ ];

[ ][ \(\gt \) | \(\lt \) | \(=\) | \(\geqslant \) | \(\leqslant \) ] \(x\) [ \(\gt \) | \(\lt \) | \(=\) | \(\geqslant \) | \(\leqslant \) ][ ];

[ ] \(\lt x\lt \) [ ].

Используй в ответе десятичную запись числа.

Ответ: \(x \in\) [ ].