Задание
Расставь части решения в правильном порядке
Упрости выражение и найди его значение.
- \(\dfrac{c+6}{(c-5)^2} \cdot \dfrac{4(c-5)}{(c-6)(c+6)}-\dfrac{4}{c-6}\)
- \(\dfrac{4-4c+20}{(c-5)(c-6)}\)
- \(\dfrac{-4(c-6)}{(c-5)(c-6)}\)
- \(\dfrac{-4}{c-5}\)
- \(\dfrac{c+6}{c^2-10c+25} : \dfrac{c^2-36}{4c-20} - \dfrac{4}{c-6}=\) [ ] \(=\dfrac{4}{(c-5)(c-6)} - \dfrac{4}{(c-6)}=\) [ ] \(=\dfrac{24-4c}{(c-5)(c-6)}=\) [ ] \(=\) [ ].
- \(\dfrac{((m+3)^2+(m-3)^2) \cdot (m+3)^2}{(m-3)(m+3) \cdot 4(m^2+9)}\)
- \(\dfrac{(2m^2+18)\cdot (m+3)}{4(m-3)(m^2+9)}\)
- \(\dfrac{m+3}{2(m-3)}\)
- \(\bigg( \dfrac{m+3}{m-3}+ \dfrac{m-3}{m+3} \bigg) : \dfrac{4m^2+36}{m^2+6m+9}=\) [ ] \(=\dfrac{(m^2+6m+9+m^2-6m+9)(m+3)}{(m-3)\cdot 4(m^2+9)}=\) [ ] \(=\dfrac{2(m^2+9)(m+3)}{4(m-3)(m^2+9)}=\) [ ].
- \(\dfrac{(a-b)(a+b)}{a^2+b^2}\)
- \(\dfrac{(a^2+b^2)(a-b)}{a^2+b^2}\)
- \(a-b\)
- \(\bigg( a+b-\dfrac{2ab}{a+b}\bigg):\dfrac{a^2+b^2}{a^2-b^2}=\dfrac{(a+b)^2-2ab}{a+b}\ \cdot\) [ ] \(=\dfrac{(a^2+2ab+b^2-2ab)\cdot (a-b)(a+b)}{(a+b)(a^2+b^2)}=\) [ ] \(=\) [ ].
- \(\dfrac{3c-c^2+2c}{c-2}:\dfrac{c^2-2c-8c+25}{c-2}\)
- \(\dfrac{c(5-c)}{(c-5)^2}\)
- \(\dfrac{-c}{c-5}\)
- \(\bigg( \dfrac{3c}{c-2}-c \bigg) : \bigg(c-\dfrac{8c-25}{c-2}\bigg)=\) [ ] \(=\dfrac{(5c-c^2)\cdot(c-2)}{(c-2)(c^2-10c+25)}=\) [ ] \(=\dfrac{-c(c-5)}{(c-5)^2}=\) [ ].
- \(\bigg( \dfrac{7^{\backslash 7}}{a(a-7)}-\dfrac{2^{\backslash 7a}}{a-7}+\dfrac{a^{\backslash a}}{7(a-7)} \bigg) : \dfrac{a^2-49}{a}\)
- \(\dfrac{(a-7)^2\cdot a}{7a(a-7)(a-7)(a+7)}\)
- \(\dfrac{1}{7(a+7)}\)
- \(\bigg( \dfrac{7}{a^2-7a} - \dfrac{2}{a-7} - \dfrac{a}{49-7a} \bigg) : \dfrac{a^2-49}{a}=\) [ ] \(=\dfrac{(49-14a+a^2)\cdot a}{7a(a-7)\cdot (a^2-49)}=\) [ ] \(=\) [ ].
- \(\bigg( \dfrac{a-2^{\backslash a+2}}{a^2-2a+4} - \dfrac{6a-13}{(a+2)(a^2-2a+4)} \bigg) \cdot \frac{5(a^3+8)}{a-3}\)
- \(\dfrac{(a^2-6a+9) \cdot 5}{a-3}\)
- \(5(a-3)\)
- \(\bigg( \dfrac{a-2}{a^2-2a+4}-\dfrac{6a-13}{a^3+8} \bigg) : \dfrac{a-3}{5a^3+40}=\) [ ] \(=\dfrac{(a^2-4-6a+13) \cdot 5(a+2)(a^2-2a+4)}{(a+2)(a^2-2a+4) \cdot (a-3)}=\) [ ] \(=\dfrac{(a-3)^2\cdot 5}{a-3}=\) [ ].