6\sin^2x+5\sin\left(\dfrac{5\pi}2+x\right)=2 \pm \dfrac{2\pi}{3} + 2\pi n \pi n - \dfrac{\pi}{6} \dfrac{\pi}{3} \dfrac{5\pi}{6} Ответ: , n\in\mathbb{Z};

Задание

Заполни пропуски

\(6\sin^2x+5\sin\left(\dfrac{5\pi}2+x\right)=2\)

\(\pm\)
\(\dfrac{2\pi}{3}\)
\(+\)
\(2\pi n\)
\(\pi n\)
\(-\)
\(\dfrac{\pi}{6}\)
\(\dfrac{\pi}{3}\)
\(\dfrac{5\pi}{6}\)

Ответ:[ ][ ][ ][ ], \(n\in\mathbb{Z}\) ;