Реши уравнения

1. \({\dfrac{\cos 5x}{\cos x}(2\cos^2 x\raisebox{-1em}{\),\(}\mathrlap{\:-}}\) \({-\sin^2 x\cos 2x-1)=1}\) ;

2. \({\dfrac{\cos 5x}{\cos x}(1-2\sin^2 x\raisebox{-1em}{\),\(}\mathrlap{\:-}}\) \({-\sin^2 x\cos 2x)=1}\) .

Ответ:

1. \(x=\) [ ], \(n\in \Z\) ;

2. \(x=\) [ ], \(n\in \Z\) .