Заполни пропуски в решении уравнения

\(8\left( \dfrac{1}{2}x-2\right) \left( \dfrac{1}{4}x^2+x+4\right) -x(x-3)^2=6x^2-46\) ;

\(8(\) [ ] \(x^3\) [ ] \()-x(x^2\) [ ] \(+9)=6x^2-46\) ;

[ ] \(-64-\) [ ]+[ ] \(-9x=6x^2-46\) ;

[ ] \(=-46\) [ ];

[ ] \(x=\) [ ];

\(x=\) [ ].