Выполни проверку корней уравнения

В процессе решения уравнения \(\sqrt{x^2-3x+31}=7\) получили корни \(x=6\) или \(x=-3\) .

Проверка.

Проверим сначала \(x=6\) :

\(\mathrlap{\sqrt{\phantom{ \raisebox{1.1em}{\kern{13em}}}}}{\phantom{00}}\) [ ] \(^2-3\cdot\) [ ] \(+31\) \(=7\) ;

\(\mathrlap{\sqrt{\phantom{ \raisebox{1.1em}{\kern{11.5em}}}}}{\phantom{00}}\) [ ] \(-\) [ ] \(+31\) \(=7\) ;

\(\mathrlap{\sqrt{\phantom{ \raisebox{1.1em}{\kern{4em}}}}}{\phantom{00}}\) [ ] \(=7\) ;

[ ] \(=7\) , [верно|неверно].

Проверим \(x=-3\) :

\(\mathrlap{\sqrt{\phantom{ \raisebox{1.1em}{\kern{14.5em}}}}}{\phantom{00}}\) [ ] \(^2-3\cdot(\) [ ] \()+31\) \(=7\) ;

\(\mathrlap{\sqrt{\phantom{ \raisebox{1.1em}{\kern{11.2em}}}}}{\phantom{00}}\) [ ] \(+\) [ ] \(+31\) \(=7\) ;

\(\mathrlap{\sqrt{\phantom{ \raisebox{1.1em}{\kern{4em}}}}}{\phantom{00}}\) [ ] \(=7\) ;

[ ] \(=7\) , [верно|неверно].

Корни запиши в порядке возрастания.

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