Заполни пропуски

Вычисли производную функции \({y = x^2 + 3.}\)

Решение.

\({\Delta y = y(x+\Delta x) - y(x) = (x \,\mathrlap{\,+}}\) \({+ \Delta x)^2+3 - (x^2 + 3) = x^2+2x\Delta x\,\mathrlap{\,+}}\) \({+\Delta x^2 - x^2 =} \) [ ];

\(\dfrac{\Delta y}{\Delta x} = \dfrac{2x\Delta x + \Delta x^2}{\Delta x} = \) [ ];

\(y' = \lim\limits\_{\Delta x\to 0}\dfrac{\Delta y}{\Delta x} = \lim\limits\_{\Delta x \to 0}(2x+\Delta x) = \) [ ].

Ответ:[ ].