Разделите многочлен \(\displaystyle 8y^{\,4}\,-6y^{\,3}\,+\,16y\,-12\) на многочлен \(\displaystyle 4y-3\) в столбик:

\(\displaystyle -\)	\(\displaystyle \phantom{\,\,}8y^{\,4}-6y^{\,3}+16y-12\)				\(\displaystyle 4y-3\)
	[ ]				[ ]
	\(\displaystyle \phantom{35x^{\,4}+2\,} -\)	[ ]
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				\(\displaystyle 0\,\,\)

и запишите разложение:

\(\displaystyle 8y^{\,4}\,-6y^{\,3}\,+\,16y\,-12=(4y-3)\cdot(\)[ ]\(\displaystyle ).\)