Задание
Разделите многочлен \(\displaystyle 40x^{\,4}-13x^{\, 3}+17x^{\,2}-26x+3\) на многочлен \(\displaystyle -8x+1\) в столбик:
| \(\displaystyle -\) | \(\displaystyle \phantom{\,\,}40x^{\,4}-13x^{\, 3}+17x^{\,2}-26x+3\) | \(\displaystyle -8x+1\) | |||||
[ ] |
[ ] | ||||||
| \(\displaystyle \phantom{2x^{\,4}} -\) |
[ ] | ||||||
[ ] | |||||||
| \(\displaystyle \phantom{ x^{\,3}x\,} -\) |
[ ] | ||||||
[ ] | |||||||
| \(\displaystyle \phantom{ xx\,\,} -\) |
[ ] | ||||||
| [ ] | |||||||
| \(\displaystyle 0\) | |||||||
Найдите недостающий множитель в разложении:
\(\displaystyle 40x^{\,4}-13x^{\, 3}+17x^{\,2}-26x+3=(-8x+1) \cdot (\)[ ]\(\displaystyle ).\)