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Найди натуральное число, записанное в виде дроби:

\(\small \cfrac {\sqrt {4+2\sqrt 3}}{\sqrt 3 +1}=\cfrac {\sqrt {3+2\sqrt 3 +1}}{\sqrt 3 +1}=\cfrac {\sqrt {(\sqrt 3 +1)^2}}{\sqrt 3 +1}=\cfrac {|\sqrt 3 +1|}{\sqrt 3 +1}=\cfrac {\sqrt 3 +1}{\sqrt 3 +1}=1\) ;

\(\small \cfrac {\sqrt {16-8\sqrt 3}}{\sqrt 3 -1}=\cfrac {\sqrt {4(4-2\sqrt 3)}}{\sqrt 3 -1}=\cfrac {2\sqrt {3-2\sqrt 3 +1}}{\sqrt 3 -1}=\cfrac {2\sqrt {(\sqrt 3 -1)^2}}{\sqrt 3 -1}=\cfrac {2|\sqrt 3 -1|}{\sqrt 3 -1}=\cfrac {2(\sqrt 3 -1)}{\sqrt 3 -1}=2\) .

а) \(\cfrac {\sqrt {3-2\sqrt 2}}{\sqrt 2 -1}=\) [ ];

б) \(\cfrac {\sqrt {11-4\sqrt 7}}{\sqrt 7 -2}=\) [ ];

в) \(\cfrac {\sqrt {20+8\sqrt 6}}{\sqrt 3 +\sqrt 2}=\) [ ];

г) \(\cfrac {\sqrt {36+18\sqrt 3}}{\sqrt 3 +1}=\) [ ];

д) \(\cfrac {\sqrt {72-18\sqrt {15}}}{\sqrt 5 -\sqrt 3}=\) [ ];

е) \(\cfrac {\sqrt {45+18\sqrt 6}}{\sqrt 3 +\sqrt 2}=\) [ ].