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Реши уравнение:

\(cos (2x - \dfrac{\pi}{4}) = -\dfrac{\sqrt{3}}{2}\)

Решение:

\(cos (2x - \dfrac{\pi}{4}) = -\dfrac{\sqrt{3}}{2}\)

\(2x -\dfrac{\pi}{4} = \) [ ] \(, n \in Z\) ;

\(2x-\dfrac{\pi}{4} = \) [ ] \(, n \in Z\) ;

\(2x = \dfrac{\pi}{4} \pm \dfrac{5\pi}{6} + 2\pi n, n \in Z\) ;

\(x1 = \dfrac{13\pi}{24} + \pi n, n \in Z\) ;

\(x2 = \) [ ] \(, n \in Z\) .

Ответ: \(x1 = \) [ ] \(, n \in Z\) ; \(x2 = \) [ ] \(, n \in Z\) .