x + 2 = \log_{6}(35 + 6^{–x}); \log_{3} (4 \cdot 3^{x} – 1) = 2x + 1. Ответ: x = ; x_{1} = ; x_{2} = .
Задание

Решиуравнение

  1. \(x+2=\log\_{6}(35+6^{–x});\)
  2. \(\log\_{3}(4\cdot3^{x}–1)=2x+1.\)

Ответ:

  1. \(x=\) [ ];
  2. \(x\_{1}=\) [ ];
    \(x\_{2}=\) [ ].