Решите уравнение \({\sqrt{2}\sin{\left(\dfrac{\pi}{12}-3x\right)}-1=0.}\) Выберите вариант ответа. \({(-1)^{n+1}\dfrac{\pi}{12}+\dfrac{\pi}{36}+\dfrac{{\pi}n}{3},n\in{\mathbf{Z}}}\) \({(-1)^{n+1}\dfrac{\pi}{4}+\dfrac{\pi}{36}+\dfrac{{\pi}n}{3},n\in{\mathbf{Z}}}\) \({(-1)^{n+1}\dfrac{\pi}{12}+\dfrac{\pi}{36}+2{{\pi}n},n\in{\mathbf{Z}}}\) \({(-1)^{n+1}\dfrac{\pi}{12}+\dfrac{\pi}{36}+2{{\pi}n},n\in{\mathbf{Z}}}\)

Задание

Решите уравнение \({\sqrt{2}\sin{\left(\dfrac{\pi}{12}-3x\right)}-1=0.}\) Выберите вариант ответа.

\({(-1)^{n+1}\dfrac{\pi}{12}+\dfrac{\pi}{36}+\dfrac{{\pi}n}{3},n\in{\mathbf{Z}}}\)
\({(-1)^{n+1}\dfrac{\pi}{4}+\dfrac{\pi}{36}+\dfrac{{\pi}n}{3},n\in{\mathbf{Z}}}\)
\({(-1)^{n+1}\dfrac{\pi}{12}+\dfrac{\pi}{36}+2{{\pi}n},n\in{\mathbf{Z}}}\)
\({(-1)^{n+1}\dfrac{\pi}{12}+\dfrac{\pi}{36}+2{{\pi}n},n\in{\mathbf{Z}}}\)