Задание
Решите уравнение \({\sin\left(\dfrac{\pi}{18}-8x\right)=1.}\)
- \({-\dfrac{{\pi}}{18}+\dfrac{{\pi}n}{4},n\in{\mathbf{Z}}}\)
- \({-\dfrac{{\pi}}{18}+2{{\pi}n},n\in{\mathbf{Z}}}\)
- \({\dfrac{5{\pi}}{72}+\dfrac{{\pi}n}{4},n\in{\mathbf{Z}}}\)
- \({\dfrac{{\pi}}{18}+\dfrac{{\pi}n}{4},n\in{\mathbf{Z}}}\)