Задание
Решите уравнение \(\frac{\cos{2x}\cos{8x}-\cos{10x}}{\cos{x}+1}=0.\) Выберете корни уравнения, принадлежащие отрезку \([0;\pi].\)
- \(0\)
- \(\frac{\pi}{8}\)
- \(\frac{\pi}{4}\)
- \(\frac{3\pi}{8}\)
- \(\frac{\pi}{2}\)
- \(\frac{5\pi}{8}\)
- \(\frac{3\pi}{4}\)
- \(\frac{7\pi}{8}\)
- \(\frac{9\pi}{8}\)
- \(\frac{5\pi}{4}\)
- \(\frac{11\pi}{8}\)
- \(\frac{3\pi}{2}\)
- \(\frac{13\pi}{8}\)
- \(\frac{7\pi}{4}\)
- \(\pi\)
- \(\frac{15\pi}{8}\)