\dfrac{2x^2+3x-9}{x^2+x-6} \ge 0 x \in (- \infty; -3)\cup (-3; 1\frac 12] \cup (2; +\infty) x \in (- \infty; 1\frac 12] \cup (2; +\infty) x \in (- \infty; -3)\cup (-3; 1\frac 12) \cup (2; +\infty) x \in [2; +\infty)

Задание

Реши неравенство

\(\dfrac{2x^2+3x-9}{x^2+x-6} \ge 0\)

\(x \in (- \infty; -3)\cup (-3; 1\frac 12] \cup (2; +\infty)\)
\(x \in (- \infty; 1\frac 12] \cup (2; +\infty)\)
\(x \in (- \infty; -3)\cup (-3; 1\frac 12) \cup (2; +\infty)\)
\( x \in [2; +\infty)\)