\dfrac{(2x-3)(x+3)}{x-4} \gt 0 x \in (-3; 1\frac 12)\cup (4; +\infty) x \in (- \infty; -3) \cup (1 \frac 12;4) x \in (- \infty; -3) x \in (4; +\infty)

Задание

Реши неравенство

\(\dfrac{(2x-3)(x+3)}{x-4} \gt 0\)

\(x \in (-3; 1\frac 12)\cup (4; +\infty)\)
\(x \in (- \infty; -3) \cup (1 \frac 12;4)\)
\(x \in (- \infty; -3)\)
\( x \in (4; +\infty)\)