2x\cdot (x^2-4x)= -a^2\cdot (a+8)= 4y\cdot \left(\dfrac{1}{4}y+y^3\right)= -\dfrac{1}{2}p^2\cdot (2p-4)
Задание

Выбери верные ответы

  1. \(2x\cdot (x^2-4x)=\) [ \(2x^3-8x^2\) | \(9x^4-2x\) | \(x^3-6x\) ]
  2. \(-a^2\cdot (a+8)=\) [ \(-2a+5\) | \(-a^3-8a^2\) | \(3a-2a^{11}\) ]
  3. \(4y\cdot \left(\dfrac{1}{4}y+y^3\right)=\) [ \(y^2+4y^4\) | \(7y-8y^3\) | \(8y^6+y\) ]
  4. \(-\dfrac{1}{2}p^2\cdot (2p-4)\) [ \(-7p-5p^3\) | \(5p^7-p^2\) | \(-p^3+2p^2\) ]