Выполни действия
\(\dfrac{x╰\,^1}{30y} + \dfrac{4╰\,^{2y}}{15} = \dfrac{x}{30y} + \dfrac{8y}{30y} = \dfrac{...}{30y}\) ;
\(\dfrac{y╰\,^3}{8x} - \dfrac{x╰\,}{6} = \dfrac{3y}{24x} - \dfrac{...}{24x} = \dfrac{...}{24x}\) ;
\(2-\dfrac{a}{3b} = \dfrac{2╰\,}{1} - \dfrac{a╰\,}{3b} = \dfrac{...}{3b} - \dfrac{...}{3b}\) ;
\(\dfrac{7╰}{a^2} - 3╰ + \dfrac{1╰\,}{a}= \dfrac{...}{a^2} - \dfrac{...}{a^2} + \dfrac{...}{a^2}\) ;
\(\dfrac{5╰}{7x^2y} - \dfrac{1╰}{4xy^3}- \dfrac{3╰}{14x^4y^2}= \dfrac{...}{28x^4y^3} + \dfrac{...}{28x^4y^3} - \dfrac{...}{28x^4y^3}\) ;
\(3╰ - \dfrac{11╰}{6a^2b} + \dfrac{7╰}{4a^3b^2} = \dfrac{...}{... \cdot a^3b^2}- ... + ...\) ;
\(\dfrac{(3+x)╰}{4(x-1)} + \dfrac{(5-x)╰}{3(x-1)}= \dfrac{3(3+x)}{12(x-1)} + \dfrac{...}{12(x-1)} = \dfrac{...}{12(x-1)}\) ;
\(\dfrac{2}{xy+y^2} - \dfrac{x-1}{x^2y+xy^2} = \dfrac{2╰\,^x}{y(...)} - \dfrac{x-1╰\,^1}{xy(...)}= \dfrac{2x-(x-1)}{xy(...)}\) ;
\(\dfrac{3b-1}{b^2-4} + \dfrac{2}{2+b} = \dfrac{3b-1}{(...)(...)} +\dfrac{2}{b+2}\) ;
\(\dfrac{3b-1}{b^2-4} + \dfrac{2}{2-b} = \dfrac{3b-1}{(...)(...)} ...\dfrac{2}{b-2}\) ;
\(x-1-\dfrac{x^2}{x+1} = \dfrac{x-1╰\,^{x+1}}{1} - \dfrac{x^2}{x+1}\) ;
\(\dfrac{2a^2}{a+2} - a +2 = \dfrac{2a^2}{a+2} - \dfrac{...}{1}\) .