Выбери верное продолжение формулы. ${\left ( \dfrac{x^2}{x^2-3} \right )}'=$ $\dfrac{{(x^2)}'⋅ (x^2-3)+{(x^2-3)}'⋅ (x^2)}{\left (x^2-3 \right )^{2}}$ $\dfrac{{(x^2-3)}'⋅ (x^2)-{(x^2)}'⋅ (x^2-3)}{\left (x^2-3 \right )^{2}}$ $\dfrac{{(x^2)}'⋅ (x^2-3)+{(x^2-3)}'⋅ (x^2)}{x^2-3 }$ $\dfrac{{(x^2)}'⋅ (x^2-3)-{(x^2-3)}'⋅ (x^2)}{\left (x^2-3 \right )^{2}}$

Задание

Выбери верное продолжение формулы.

\({\left ( \dfrac{x^2}{x^2-3} \right )}'=\)

\(\dfrac{{(x^2)}'⋅ (x^2-3)+{(x^2-3)}'⋅ (x^2)}{\left (x^2-3 \right )^{2}}\)
\(\dfrac{{(x^2-3)}'⋅ (x^2)-{(x^2)}'⋅ (x^2-3)}{\left (x^2-3 \right )^{2}}\)
\(\dfrac{{(x^2)}'⋅ (x^2-3)+{(x^2-3)}'⋅ (x^2)}{x^2-3 }\)
\(\dfrac{{(x^2)}'⋅ (x^2-3)-{(x^2-3)}'⋅ (x^2)}{\left (x^2-3 \right )^{2}}\)