Выбери верное продолжение формулы. ${\left ( \dfrac{x^2}{x^2-1} \right )}'=$ $\dfrac{{(x^2)}'⋅ (x^2-1)+{(x^2-1)}'⋅ (x^2)}{\left (x^2-1 \right )^{2}}$ $\dfrac{{(x^2-1)}'⋅ (x^2)-{(x^2)}'⋅ (x^2-1)}{\left (x^2-1 \right )^{2}}$ $\dfrac{{(x^2)}'⋅ (x^2-1)+{(x^2-1)}'⋅ (x^2)}{x^2-1 }$ $\dfrac{{(x^2)}'⋅ (x^2-1)-{(x^2-1)}'⋅ (x^2)}{\left (x^2-1 \right )^{2}}$

Задание

Выбери верное продолжение формулы.

\({\left ( \dfrac{x^2}{x^2-1} \right )}'=\)

\(\dfrac{{(x^2)}'⋅ (x^2-1)+{(x^2-1)}'⋅ (x^2)}{\left (x^2-1 \right )^{2}}\)
\(\dfrac{{(x^2-1)}'⋅ (x^2)-{(x^2)}'⋅ (x^2-1)}{\left (x^2-1 \right )^{2}}\)
\(\dfrac{{(x^2)}'⋅ (x^2-1)+{(x^2-1)}'⋅ (x^2)}{x^2-1 }\)
\(\dfrac{{(x^2)}'⋅ (x^2-1)-{(x^2-1)}'⋅ (x^2)}{\left (x^2-1 \right )^{2}}\)