Упрости выражения \frac{3b^2+6b+3}{b^3-8}\cdot \frac{2b^2+4b+8}{9b+9}= . \frac{a^2-81b^2}{49a^2-25b^2}\colon \frac{a^2+18ab+81b^2}{49a^2-70ab+25b^2}= . \frac{(a^n-3b^n)^2+12a^nb^n}{a^2-b^2}\colon \frac{a^{2n}-9b^{2n}}{a-b}= .

Задание

Упрости выражения

\(\frac{3b^2+6b+3}{b^3-8}\cdot \frac{2b^2+4b+8}{9b+9}=\) [ \(\frac {2(b+1)}{3(b-2)}\) | \(\frac {3b^2+6b+3}{9b+9}\) | \(\frac {2(b^2+2b+1)}{3(b-2)(b+1)}\) ].
\(\frac{a^2-81b^2}{49a^2-25b^2}\colon \frac{a^2+18ab+81b^2}{49a^2-70ab+25b^2}=\) [ \(-1\) | \(\frac {7a^2-68ab+45b^2}{7a^2+68ab+45b^2}\) | \(1\) ].
\(\frac{(a^n-3b^n)^2+12a^nb^n}{a^2-b^2}\colon \frac{a^{2n}-9b^{2n}}{a-b}=\) [ \(\frac {a^n+3b^n}{(a+b)(a^n-3b^n)}\) | \(a^n+3b^n\) | \(\frac {1}{a+b}\) ].