Задание
Вычисли
\(\sqrt 2 \cdot \sqrt 8=\sqrt {2 \cdot 8}=\sqrt {16}=4\) ;
\(\dfrac {\sqrt {27}}{\sqrt 3}=\sqrt \dfrac{27}{3}=\sqrt 9=3\) .
а) \(\sqrt 3 \cdot \sqrt {27}=\) [ ];
б) \(\sqrt 2 \cdot \sqrt {18}=\) [ ];
в) \(\sqrt {32} \cdot \sqrt 2=\) [ ];
г) \(\sqrt 5 \cdot \sqrt {45}=\) [ ];
д) \(\dfrac {\sqrt {32}} {\sqrt 8}=\) [ ];
е) \(\dfrac {\sqrt {75}} {\sqrt {12}}=\) [ ].