\sqrt 2 \cdot \sqrt 8=\sqrt {2 \cdot 8}=\sqrt {16}=4; \dfrac {\sqrt {27}}{\sqrt 3}=\sqrt \dfrac{27}{3}=\sqrt 9=3. а) \sqrt 3 \cdot \sqrt {27}= ; б) \sqrt 2 \cdot \sqrt {18}= ; в) \sqrt {32} \cdot \sqrt 2= ; г) \sqrt 5 \cdot \sqrt {45}= ; д) \dfrac {\sqrt {32}} {\sqrt 8}= ; е) \dfrac {\sqrt {75}} {\sqrt {12}}= .
Задание

Вычисли

\(\sqrt 2 \cdot \sqrt 8=\sqrt {2 \cdot 8}=\sqrt {16}=4\) ;

\(\dfrac {\sqrt {27}}{\sqrt 3}=\sqrt \dfrac{27}{3}=\sqrt 9=3\) .

а) \(\sqrt 3 \cdot \sqrt {27}=\) [ ];

б) \(\sqrt 2 \cdot \sqrt {18}=\) [ ];

в) \(\sqrt {32} \cdot \sqrt 2=\) [ ];

г) \(\sqrt 5 \cdot \sqrt {45}=\) [ ];

д) \(\dfrac {\sqrt {32}} {\sqrt 8}=\) [ ];

е) \(\dfrac {\sqrt {75}} {\sqrt {12}}=\) [ ].