Сократи дроби \dfrac{3a^2-3ab}{9ab} =\dfrac{\,^{1}\,\bcancel{3}a(a-b)}{\,_{1}\,\bcancel{3}a\cdot 3b} = . \dfrac{4xy+4xz}{6xy} = .
Задание

Сократи дроби

  1. \(\dfrac{3a^2-3ab}{9ab} =\dfrac{\,^{1}\,\bcancel{3}a(a-b)}{\,\_{1}\,\bcancel{3}a\cdot 3b} =\) [ ]
    .
  2. \(\dfrac{4xy+4xz}{6xy} =\) [ ]
    .