Решите уравнение \(\sin x = \frac{\pi}{2}\) .
корней нет
\(x = 1\)
\(x = \frac{\pi}{2} + 2\pi n, n\in \mathbb{Z}; x = -\frac{\pi}{2} + 2\pi k, k\in \mathbb{Z}\)
\(x = \frac{\pi}{2} + \pi n, n\in \mathbb{Z}\)