Решите уравнение \({\cos{\left(x+\dfrac{\pi}{6}\right)}=\dfrac{\sqrt{2}}{2}.}\) Выберите вариант ответа. \({\dfrac{5\pi}{12}+2{\pi}n,n\in{\mathbf{Z}};-\dfrac{\pi}{12}+2{\pi}k,k\in{\mathbf{Z}}}\) \({\dfrac{5\pi}{12}+2{\pi}n,n\in{\mathbf{Z}};-\dfrac{5\pi}{12}+2{\pi}k,k\in{\mathbf{Z}}}\) \({\dfrac{\pi}{12}+2{\pi}n,n\in{\mathbf{Z}};-\dfrac{\pi}{12}+2{\pi}k,k\in{\mathbf{Z}}}\) \({-\dfrac{5\pi}{12}+2{\pi}n,n\in{\mathbf{Z}};\dfrac{\pi}{12}+2{\pi}k,k\in{\mathbf{Z}}}\)

Задание

Решите уравнение \({\cos{\left(x+\dfrac{\pi}{6}\right)}=\dfrac{\sqrt{2}}{2}.}\) Выберите вариант ответа.

\({\dfrac{5\pi}{12}+2{\pi}n,n\in{\mathbf{Z}};-\dfrac{\pi}{12}+2{\pi}k,k\in{\mathbf{Z}}}\)
\({\dfrac{5\pi}{12}+2{\pi}n,n\in{\mathbf{Z}};-\dfrac{5\pi}{12}+2{\pi}k,k\in{\mathbf{Z}}}\)
\({\dfrac{\pi}{12}+2{\pi}n,n\in{\mathbf{Z}};-\dfrac{\pi}{12}+2{\pi}k,k\in{\mathbf{Z}}}\)
\({-\dfrac{5\pi}{12}+2{\pi}n,n\in{\mathbf{Z}};\dfrac{\pi}{12}+2{\pi}k,k\in{\mathbf{Z}}}\)