Решите уравнение \({2\cos{\left(\dfrac{\pi}{8}-3x\right)+1=0}.}\) Выберите вариант ответа. \({\dfrac{19\pi}{72}+\dfrac{2{\pi}n}{3},n\in{\mathbf{Z}};-\dfrac{13\pi}{72}+\dfrac{2{\pi}k}{3},k\in{\mathbf{Z}}}\) \({\dfrac{19\pi}{72}+{2{\pi}n},n\in{\mathbf{Z}};-\dfrac{13\pi}{72}+{2{\pi}k},k\in{\mathbf{Z}}}\) \({-\dfrac{19\pi}{72}+\dfrac{2{\pi}n}{3},n\in{\mathbf{Z}};\dfrac{13\pi}{72}+\dfrac{2{\pi}k}{3},k\in{\mathbf{Z}}}\) \({\dfrac{11\pi}{72}+\dfrac{2{\pi}n}{3},n\in{\mathbf{Z}};-\dfrac{5\pi}{72}+\dfrac{2{\pi}k}{3},k\in{\mathbf{Z}}}\)

Задание

Решите уравнение \({2\cos{\left(\dfrac{\pi}{8}-3x\right)+1=0}.}\) Выберите вариант ответа.

\({\dfrac{19\pi}{72}+\dfrac{2{\pi}n}{3},n\in{\mathbf{Z}};-\dfrac{13\pi}{72}+\dfrac{2{\pi}k}{3},k\in{\mathbf{Z}}}\)
\({\dfrac{19\pi}{72}+{2{\pi}n},n\in{\mathbf{Z}};-\dfrac{13\pi}{72}+{2{\pi}k},k\in{\mathbf{Z}}}\)
\({-\dfrac{19\pi}{72}+\dfrac{2{\pi}n}{3},n\in{\mathbf{Z}};\dfrac{13\pi}{72}+\dfrac{2{\pi}k}{3},k\in{\mathbf{Z}}}\)
\({\dfrac{11\pi}{72}+\dfrac{2{\pi}n}{3},n\in{\mathbf{Z}};-\dfrac{5\pi}{72}+\dfrac{2{\pi}k}{3},k\in{\mathbf{Z}}}\)