Решите неравенство \((5x+1)(3x-1)>(4x-1)(x+2)\) . \(\left(-\infty;\frac{9-\sqrt{37}}{22}\right)\cup\left(\frac{9+\sqrt{37}}{22}; +\infty\right)\) \(\left(-\infty;\frac{9-\sqrt{37}}{22}\right]\cup\left[\frac{9+\sqrt{37}}{22}; +\infty\right)\) \(\left(\frac{9-\sqrt{37}}{22}; \frac{9+\sqrt{37}}{22}\right)\) \(\left(\frac{-9-\sqrt{37}}{22}; \frac{-9+\sqrt{37}}{22}\right)\) \(\left(-\infty;\frac{-9-\sqrt{37}}{22}\right)\cup\left(\frac{-9+\sqrt{37}}{22}; +\infty\right)\)

Задание

Решите неравенство \((5x+1)(3x-1)\gt (4x-1)(x+2)\) .

\(\left(-\infty;\frac{9-\sqrt{37}}{22}\right)\cup\left(\frac{9+\sqrt{37}}{22}; +\infty\right)\)
\(\left(-\infty;\frac{9-\sqrt{37}}{22}\right]\cup\left[\frac{9+\sqrt{37}}{22}; +\infty\right)\)
\(\left(\frac{9-\sqrt{37}}{22}; \frac{9+\sqrt{37}}{22}\right)\)
\(\left(\frac{-9-\sqrt{37}}{22}; \frac{-9+\sqrt{37}}{22}\right)\)
\(\left(-\infty;\frac{-9-\sqrt{37}}{22}\right)\cup\left(\frac{-9+\sqrt{37}}{22}; +\infty\right)\)