Реши уравнения, заполняя пропуски

1. \(8x + 11x^2 = 0\)

• \(x(8 + 11x)\)
• \(x\)
• \(-\dfrac{8}{11}\)
• \(0\)
• \(\dfrac{8}{11}\)

[ ] \(= 0\) ;

[ ] \(= 0\) , или \(x = \) [ ].

Ответ: \(x\_1 =\) [ ], \(x\_2 = -\) [ ].

2. \(\dfrac{2x - 5}{x - 2} = 0\)

• \( \begin{cases} 2x - 5 = 0, \space x = \dfrac{5}{2} \\ x - 2 \kern{0.27em}{=}\mathllap{/\,}\kern{0.27em} 0 \end{cases} \)
• \(2,5\)
• \(2\)
• \(0,5\)
• \(x = 2,5\)

[ ]

Если \(x =\) [ ], то \(x -\) [ ] \(=\) [ ] \(\kern{0.27em}{=}\mathllap{/\,}\kern{0.27em} 0\) .

Ответ:[ ].

3. \(9x^3 - x = 0\)

• \(x(9x^2 - 1)\)
• \(x(3x - 1)(3x + 1)\)
• \(0\)
• \(3x - 1\)
• \(3x + 1\)
• \(x\)
• \(\dfrac{1}{3}\)
• \(-\dfrac{1}{3}\)
• \(x\_1 = 0\)
• \(x\_2 = \dfrac{1}{3}\)
• \(x\_3 = -\dfrac{1}{3}\)

[ ] \(= 0\) , [ ] \(= 0\) ;

\(x =\) [ ], или [ ] \(= 0\) , или [ ] \(= 0\) ,

т. е. [ ] \(= 0\) , или \(x =\) [ ], или \(x =\) [ ].

Ответ:[ ]; [ ]; [ ].