$\tg\left(3x+\dfrac{\pi}{3}\right)=0$ $x=-\dfrac{\pi}{18}+\dfrac{\pi k}{3},\;k\in\mathbb {Z}$ $x=-\dfrac{\pi}{9}+\pi k,\;k\in\mathbb {Z}$ $x=-\dfrac{\pi}{6}+\dfrac{\pi k}{3},\;k\in\mathbb {Z}$ $x=-\dfrac{\pi}{9}+\dfrac{\pi k}{3},\;k\in\mathbb {Z}$

Задание

Реши уравнение.

\(\tg\left(3x+\dfrac{\pi}{3}\right)=0\)

Выбери верный вариант.

\(x=-\dfrac{\pi}{18}+\dfrac{\pi k}{3},\;k\in\mathbb {Z}\)
\(x=-\dfrac{\pi}{9}+\pi k,\;k\in\mathbb {Z}\)
\(x=-\dfrac{\pi}{6}+\dfrac{\pi k}{3},\;k\in\mathbb {Z}\)
\(x=-\dfrac{\pi}{9}+\dfrac{\pi k}{3},\;k\in\mathbb {Z}\)