Реши тригонометрическое уравнение \dfrac{2\cos^2x-7\sin x+2}{2\cos x-\sqrt3}=0 \frac{5\pi}{6}+\pi n,n\in\mathbb{Z} \frac{5\pi}{6}+2\pi n,n\in\mathbb{Z} -\frac{\pi}{6}+\pi n,n\in\mathbb{Z} -\frac{\pi}{6}+2\pi n,n\in\mathbb{Z} \pm\frac{\pi}{6}+\pi n,n\in\mathbb{Z} \pm\frac{\pi}{6}+2\pi n,n\in\mathbb{Z}

Задание

Реши тригонометрическое уравнение

\(\dfrac{2\cos^2x-7\sin x+2}{2\cos x-\sqrt3}=0\)

\(\frac{5\pi}{6}+\pi n,n\in\mathbb{Z}\)
\(\frac{5\pi}{6}+2\pi n,n\in\mathbb{Z}\)
\(-\frac{\pi}{6}+\pi n,n\in\mathbb{Z}\)
\(-\frac{\pi}{6}+2\pi n,n\in\mathbb{Z}\)
\(\pm\frac{\pi}{6}+\pi n,n\in\mathbb{Z}\)
\(\pm\frac{\pi}{6}+2\pi n,n\in\mathbb{Z}\)