Разделите многочлен \(\displaystyle s^{\,3}-15s+4\) на многочлен \(\displaystyle s+4\) в столбик:

\(\displaystyle -\)	\(\displaystyle \phantom{\,\,}s^{\,3}-15s+4\)				\(\displaystyle s+4\)
	[ ]				[ ]
	\(\displaystyle -\)	[ ]
		[ ]
		\(\displaystyle \phantom{ xxxxx} -\)		[ ]
				[ ]
				\(\displaystyle 0\)

и запишите разложение:

\(\displaystyle s^{\,3}-15s+4=(s+4)\cdot \big(\)[ ]\(\displaystyle \big).\)