Приведи дроби к знаменателю 60. а) \;\raisebox{-0.2em}{$^{2/}$}\!\!\raisebox{-1.1em}{$\dfrac{1}{30}=\dfrac{2}{60}\textsf{;}\kern{2.6em} $} б) \raisebox{-1.1em}{$\dfrac{11}{20}= $}\mathrlap{\,\raisebox{-1.1em}{$\def\arraystretch{1.05}\begin{array}{c}\, \phantom{232} \,\\ \hline 60 \\ \end{array} $}} \raisebox{-1.0em}{$ \textsf{;} $} в) \raisebox{-1.1em}{$\dfrac{7}{10}= $}\mathrlap{\,\raisebox{-1.1em}{$\def\arraystretch{1.05}\begin{array}{c}\, \phantom{232} \,\\ \hline 60 \\ \end{array} $}} \raisebox{-1.0em}{$ \textsf{;} $}\kern{1.1em} г) \raisebox{-1.1em}{$\dfrac{4}{15}= $}\mathrlap{\,\raisebox{-1.1em}{$\def\arraystretch{1.05}\begin{array}{c}\, \phantom{332} \,\\ \hline 60 \\ \end{array} $}} \raisebox{-1.0em}{$ \textsf{;} $} д) \raisebox{-1.1em}{$\dfrac{5}{12}= $}\mathrlap{\,\raisebox{-1.1em}{$\def\arraystretch{1.05}\begin{array}{c}\, \phantom{322} \,\\ \hline 60 \\ \end{array} $}} \raisebox{-1.0em}{$ \textsf{;} $}\kern{1.1em} е) \raisebox{-1.1em}{$\dfrac{5}{6}= $}\mathrlap{\,\raisebox{-1.1em}{$\def\arraystretch{1.05}\begin{array}{c}\, \phantom{332} \,\\ \hline 60 \\ \end{array} $}} \raisebox{-1.0em}{$ \textsf{;} $} ж) \,\raisebox{-1.1em}{$\dfrac{3}{4}= $}\mathrlap{\,\raisebox{-1.1em}{$\def\arraystretch{1.05}\begin{array}{c}\, \phantom{232} \,\\ \hline 60 \\ \end{array} $}} \raisebox{-1.0em}{$ \textsf{;} $}\kern{1.4em} з) \raisebox{-1.1em}{$\dfrac{2}{3}= $}\mathrlap{\,\raisebox{-1.1em}{$\def\arraystretch{1.05}\begin{array}{c}\, \phantom{332} \,\\ \hline 60 \\ \end{array} $}} \raisebox{-1.0em}{$ . $}
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Приведи дроби к знаменателю \(60\) .

а) \(\;\raisebox{-0.2em}{\)^{2/}\(}\!\!\raisebox{-1.1em}{\)\dfrac{1}{30}=\dfrac{2}{60}\textsf{;}\kern{2.6em}\(}\) б) \(\raisebox{-1.1em}{\)\dfrac{11}{20}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\def\arraystretch{1.05}\begin{array}{c}, \phantom{232} ,\ \hline60\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \textsf{;} \(}\)

в) \(\raisebox{-1.1em}{\)\dfrac{7}{10}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\def\arraystretch{1.05}\begin{array}{c}, \phantom{232} ,\ \hline60\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \textsf{;} \(}\kern{1.1em}\) г) \(\raisebox{-1.1em}{\)\dfrac{4}{15}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\def\arraystretch{1.05}\begin{array}{c}, \phantom{332} ,\ \hline60\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \textsf{;} \(}\)

д) \(\raisebox{-1.1em}{\)\dfrac{5}{12}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\def\arraystretch{1.05}\begin{array}{c}, \phantom{322} ,\ \hline60\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \textsf{;} \(}\kern{1.1em}\) е) \(\raisebox{-1.1em}{\)\dfrac{5}{6}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\def\arraystretch{1.05}\begin{array}{c}, \phantom{332} ,\ \hline60\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \textsf{;} \(}\)

ж) \(\,\raisebox{-1.1em}{\)\dfrac{3}{4}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\def\arraystretch{1.05}\begin{array}{c}, \phantom{232} ,\ \hline60\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \textsf{;} \(}\kern{1.4em}\) з) \(\raisebox{-1.1em}{\)\dfrac{2}{3}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\def\arraystretch{1.05}\begin{array}{c}, \phantom{332} ,\ \hline60\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) . \(}\)

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