Приведи дроби к знаменателю 48. а) \;\raisebox{-0.2em}{$^{24/}$}\!\!\raisebox{-1.1em}{$\dfrac{1}{2}=\dfrac{24}{48};\kern{2.6em} $} б) \,\raisebox{-1.1em}{$\dfrac{2}{3}= $}\mathrlap{\,\raisebox{-1.1em}{$\begin{array}{c}\, \phantom{232} \,\\ \hline 48 \\ \end{array} $}} \raisebox{-1.0em}{$ \text{;} $} в) \,\raisebox{-1.1em}{$\dfrac{3}{4}= $}\mathrlap{\,\raisebox{-1.1em}{$\begin{array}{c}\, \phantom{232} \,\\ \hline 48 \\ \end{array} $}} \raisebox{-1.0em}{$ \text{;} $}\kern{1.2em} г) \,\raisebox{-1.1em}{$\dfrac{5}{6}= $}\mathrlap{\,\raisebox{-1.1em}{$\begin{array}{c}\, \phantom{332} \,\\ \hline 48 \\ \end{array} $}} \raisebox{-1.0em}{$ \text{;} $} д) \,\raisebox{-1.1em}{$\dfrac{7}{8}= $}\mathrlap{\,\raisebox{-1.1em}{$\begin{array}{c}\, \phantom{322} \,\\ \hline 48 \\ \end{array} $}} \raisebox{-1.0em}{$ \text{;} $}\kern{1.2em} е) \raisebox{-1.1em}{$\dfrac{5}{12}= $}\mathrlap{\,\raisebox{-1.1em}{$\begin{array}{c}\, \phantom{332} \,\\ \hline 48 \\ \end{array} $}} \raisebox{-1.0em}{$ \text{;} $} ж) \raisebox{-1.1em}{$\dfrac{9}{16}= $}\mathrlap{\,\raisebox{-1.1em}{$\begin{array}{c}\, \phantom{232} \,\\ \hline 48 \\ \end{array} $}} \raisebox{-1.0em}{$ \text{;} $}\kern{0.8em} з) \raisebox{-1.1em}{$\dfrac{5}{24}= $}\mathrlap{\,\raisebox{-1.1em}{$\begin{array}{c}\, \phantom{332} \,\\ \hline 48 \\ \end{array} $}} \raisebox{-1.0em}{$ \text{.} $}
Задание

Заполни пропуски

Приведи дроби к знаменателю \(48\) .

а) \(\;\raisebox{-0.2em}{\)^{24/}\(}\!\!\raisebox{-1.1em}{\)\dfrac{1}{2}=\dfrac{24}{48};\kern{2.6em}\(}\) б) \(\,\raisebox{-1.1em}{\)\dfrac{2}{3}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\begin{array}{c}, \phantom{232} ,\ \hline48\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \text{;} \(}\)

в) \(\,\raisebox{-1.1em}{\)\dfrac{3}{4}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\begin{array}{c}, \phantom{232} ,\ \hline48\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \text{;} \(}\kern{1.2em}\) г) \(\,\raisebox{-1.1em}{\)\dfrac{5}{6}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\begin{array}{c}, \phantom{332} ,\ \hline48\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \text{;} \(}\)

д) \(\,\raisebox{-1.1em}{\)\dfrac{7}{8}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\begin{array}{c}, \phantom{322} ,\ \hline48\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \text{;} \(}\kern{1.2em}\) е) \(\raisebox{-1.1em}{\)\dfrac{5}{12}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\begin{array}{c}, \phantom{332} ,\ \hline48\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \text{;} \(}\)

ж) \(\raisebox{-1.1em}{\)\dfrac{9}{16}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\begin{array}{c}, \phantom{232} ,\ \hline48\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \text{;} \(}\kern{0.8em}\) з) \(\raisebox{-1.1em}{\)\dfrac{5}{24}=\(}\) \(\mathrlap{\,\raisebox{-1.1em}{\)\begin{array}{c}, \phantom{332} ,\ \hline48\ \end{array} \(}}\) [ ] \(\raisebox{-1.0em}{\) \text{.} \(}\)