Задание
Основано на упр. 1, стр. 20
Выбери правильные ответы
Найди область определения каждой функции.
\(y = \arcsin (2 \cos x)\) ;
- \(- \cfrac{\pi}{4} \le x \le \cfrac{\pi}{4}\) .
- \(- \cfrac{\pi}{3} \le x \le \cfrac{\pi}{3}\) .
- \(\cfrac{\pi}{3} \le x \le \cfrac{2\pi}{3}\) .
- \(- \cfrac{\pi}{6} \le x \le \cfrac{\pi}{6}\) .
\(y = \arccos (2 \sin x)\) ;
- \(- \cfrac{\pi}{4} \le x \le \cfrac{\pi}{4}\) .
- \(- \cfrac{\pi}{3} \le x \le \cfrac{\pi}{3}\) .
- \(- \cfrac{\pi}{6} \le x \le \cfrac{\pi}{6}\) .
- \(- \arccos \cfrac{2}{\pi} \le x \le \arccos \cfrac{2}{\pi}\) .
\(y = \arcsin (\sqrt{2} \sin x)\) ;
- \(- \cfrac{\pi}{4} \le x \le \cfrac{\pi}{4}\) .
- \(- \cfrac{\pi}{3} \le x \le \cfrac{\pi}{3}\) .
- \(- \cfrac{\pi}{6} \le x \le \cfrac{\pi}{6}\) .
- \(- \arccos \cfrac{2}{\pi} \le x \le \arccos \cfrac{2}{\pi}\) .
\(y = \arccos \left( \cfrac{\pi}{2} \cos x \right)\) ;
- \(- \cfrac{\pi}{4} \le x \le \cfrac{\pi}{4}\) .
- \(- \arccos \cfrac{2}{\pi} \le x \le \arccos \cfrac{2}{\pi}\) .
- \(- \cfrac{\pi}{6} \le x \le \cfrac{\pi}{6}\) .
- \(\pi - \arccos \cfrac{2}{\pi} \le x \le \arccos \cfrac{2}{\pi}\) .
\(y = \arcsin ( \tg x)\) ;
- \(- \cfrac{\pi}{4} \le x \le \cfrac{\pi}{4}\) .
- \(- \cfrac{\pi}{3} \le x \le \cfrac{\pi}{3}\) .
- \(- \cfrac{\pi}{6} \le x \le \cfrac{\pi}{6}\) .
- \(- \arccos \cfrac{2}{\pi} \le x \le \arccos \cfrac{2}{\pi}\) .
\(y = \arccos (\tg x)\) ;
- \(- \cfrac{\pi}{3} \le x \le \cfrac{\pi}{3}\) .
- \(- \cfrac{\pi}{6} \le x \le \cfrac{\pi}{6}\) .
- \(- \arccos \cfrac{2}{\pi} \le x \le \arccos \cfrac{2}{\pi}\) .
- \(- \cfrac{\pi}{4} \le x \le \cfrac{\pi}{4}\) .