Нахождение производной сложной функции f(x)=\ctg \left(\dfrac{\pi}6-4x\right) \textcolor{white}{\boxed{\textcolor{black}{f'(x)=\dfrac 1{\sin^2\left(\frac{\pi}6-4x\right)}}}} \textcolor{white}{\boxed{\textcolor{black}{f'(x)=\dfrac 4{\sin^2\left(\frac{\pi}6-4x\right)}}}} \textcolor{white}{\boxed{\textcolor{black}{f'(x)=-\dfrac 1{\sin^2\left(\frac{\pi}6-4x\right)}}}} \textcolor{white}{\boxed{\textcolor{black}{f'(x)=-\dfrac 4{\sin^2\left(\frac{\pi}6-4x\right)}}}}

Задание

Нахождение производной сложной функции

\(f(x)=\ctg \left(\dfrac{\pi}6-4x\right)\)

\(\textcolor{white}{\boxed{\textcolor{black}{f'(x)=\dfrac 1{\sin^2\left(\frac{\pi}6-4x\right)}}}}\)
\(\textcolor{white}{\boxed{\textcolor{black}{f'(x)=\dfrac 4{\sin^2\left(\frac{\pi}6-4x\right)}}}}\)
\(\textcolor{white}{\boxed{\textcolor{black}{f'(x)=-\dfrac 1{\sin^2\left(\frac{\pi}6-4x\right)}}}}\)
\(\textcolor{white}{\boxed{\textcolor{black}{f'(x)=-\dfrac 4{\sin^2\left(\frac{\pi}6-4x\right)}}}}\)