(-\infty;2] (-\infty;40)\cup(40;+\infty) (-\infty;+\infty) (-\infty;0)\cup(0;+\infty) (2;+\infty) [2;+\infty) f(x) = 19 -2x, D(f)= f(x) = \dfrac{40}{x}, D(f)= f(x) = \sqrt{x-2}, D(f)=

Задание

Заполни пропуски

\((-\infty;2]\)
\((-\infty;40)\cup(40;+\infty)\)
\((-\infty;+\infty)\)
\((-\infty;0)\cup(0;+\infty)\)
\((2;+\infty)\)
\([2;+\infty)\)

\(f(x) = 19 -2x,\) \(D(f)=\) [ ]

\(f(x) = \dfrac{40}{x},\) \(D(f)=\) [ ]

\(f(x) = \sqrt{x-2},\) \(D(f)=\) [ ]