а) \dfrac{\sqrt{3}+\sqrt{2}}{\sqrt{2}\cdot(\sqrt{3}-\sqrt{2})^2}-\dfrac{\sqrt{3}-\sqrt{2}}{\sqrt{2}\cdot(\sqrt{3}+\sqrt{2})^2}= ; б) \dfrac{\sqrt{6}-\sqrt{5}}{\sqrt{5}\cdot(\sqrt{6}+\sqrt{5})^2}-\dfrac{\sqrt{6}+\sqrt{5}}{\sqrt{5}\cdot(\sqrt{6}-\sqrt{5})^2}= .

Задание

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Найди значение выражения:

а) \(\dfrac{\sqrt{3}+\sqrt{2}}{\sqrt{2}\cdot(\sqrt{3}-\sqrt{2})^2}-\dfrac{\sqrt{3}-\sqrt{2}}{\sqrt{2}\cdot(\sqrt{3}+\sqrt{2})^2}=\) [ ];

б) \(\dfrac{\sqrt{6}-\sqrt{5}}{\sqrt{5}\cdot(\sqrt{6}+\sqrt{5})^2}-\dfrac{\sqrt{6}+\sqrt{5}}{\sqrt{5}\cdot(\sqrt{6}-\sqrt{5})^2}=\) [ ].