\({4\cfrac{5}{8}-4\cfrac{5}{8}=\left(4+\cfrac{5}{8}\right)-\left(4+\cfrac{5}{8}\right)\raisebox{-1.5em}{\),\(}\mathrlap{\,=}}\)

\(\begin{array}{r} - \\ \end{array} \kern{-1.0em} \begin{array}{l}43 \\40 \\ \hline \end{array} \begin{array}{|l}10 \, \text{— знаменатель} \\ \hline\text{\textcircled 4} \, \text{— целая часть} \end{array} \newline \kern{ 0.5em} \begin{array}{r} - \\ \end{array} \kern{-1.0em} \begin{array}{r}4 \, \text{— числитель} \end{array} \)

Тогда \(4\dfrac{3}{10}\)

\(\Gamma^{\phantom{i}j}\_{i\phantom{j}k}\)