\sqrt{\dfrac{3a^2b^6c^2}{11}}\cdot \dfrac{\sqrt{11a}}{\sqrt{a^3b^6c^2}}= \sqrt{\dfrac{5abc^6}{31}}\cdot \dfrac{\sqrt{31a}}{\sqrt{abc^4}} = \sqrt{\dfrac{5a^2bc^5}{31}}\cdot \dfrac{\sqrt{31a}}{\sqrt{abc^3}} =
Логотип SimpleЦДЗ

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Задание
  1. \(\sqrt{\dfrac{3a^2b^6c^2}{11}}\cdot \dfrac{\sqrt{11a}}{\sqrt{a^3b^6c^2}}=\) [ ]
  2. \(\sqrt{\dfrac{5abc^6}{31}}\cdot \dfrac{\sqrt{31a}}{\sqrt{abc^4}} = \) [ ]
  3. \(\sqrt{\dfrac{5a^2bc^5}{31}}\cdot \dfrac{\sqrt{31a}}{\sqrt{abc^3}} = \) [ ]

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