$x⋅4=52$ $x=$ $y:9-28=32$ $y=$ $(24+d):8=7$ $d=$ $800:(a⋅9+8)=10$ $a=$
Задание

Реши уравнения

\(x⋅4=52\)
\(x=\) [ ]
\(y:9-28=32\)
\(y=\) [ ]
\((24+d):8=7\)
\(d=\) [ ]
\(800:(a⋅9+8)=10\)
\(a=\) [ ]