\log_3 \log_28 = . \log_{12}252 - \log_{12}1,75 = . \dfrac{\log_47}{\log_{64}7} = .
Задание

Вычисли и запиши ответ

  1. \(\log\_3 \log\_28 = \) [ ].
  2. \(\log\_{12}252 - \log\_{12}1,75 = \) [ ].
  3. \(\dfrac{\log\_47}{\log\_{64}7} = \) [ ].