Задание
Укажите решение неравенства \(\ctg{x}\le\frac{\sqrt{2}}{2}.\)
- \([\frac{\pi}{4}+\pi n; \frac{\pi}{2}+\pi n), n\in Z\)
- \([\frac{\pi}{4}+\pi n; \frac{\pi}{2}+\pi n], n\in Z\)
- \([\arcctg(\frac{\sqrt{2}}{2})+\pi n; \pi+\pi n), n\in Z\)
- \([\arcctg(\frac{\sqrt{2}}{2})+\pi n; \frac{\pi}{2}+\pi n], n\in Z\)