Сравните числа \(\dfrac{8}{17}\) и \(\dfrac{1}{2 + \sqrt{17-12\sqrt{2}}}\) . \(\dfrac{8}{17} > \dfrac{1}{2 + \sqrt{17-12\sqrt{2}}}\) \(\dfrac{8}{17} < \dfrac{1}{2 + \sqrt{17-12\sqrt{2}}}\) \(\dfrac{8}{17} = \dfrac{1}{2 + \sqrt{17-12\sqrt{2}}}\)
Задание

Сравните числа \(\dfrac{8}{17}\) и \(\dfrac{1}{2 + \sqrt{17-12\sqrt{2}}}\) .

  • \(\dfrac{8}{17} \gt \dfrac{1}{2 + \sqrt{17-12\sqrt{2}}}\)
  • \(\dfrac{8}{17} \lt \dfrac{1}{2 + \sqrt{17-12\sqrt{2}}}\)
  • \(\dfrac{8}{17} = \dfrac{1}{2 + \sqrt{17-12\sqrt{2}}}\)