Задание
Сократи дробь
а) \(\dfrac{x^2+5x+4}{x^2-1}=\dfrac{(...)(...)}{(x-1)(...)}=...\) ;
\(x^2+5x+4=0\) , \(x\_1=...\) , \(x\_2=...\) ;
\(x^2+5x+4=(...)(...)\) .
б) \(\dfrac{x^2+2x}{x^2-x-6}=\dfrac{x(...)}{(...)(...)}=...\) ;
\(x^2-x-6=0\) , \(x\_1=...\) , \(x\_2=...\) ;
\(x^2-x-6=(...)(...)\) .
в) \(\dfrac{x^2-2x+1}{x^2+7x-8}=\dfrac{(...)^2}{(...)(...)}=...\) ;
\(x^2+7x-8=0\) , \(x\_1=...\) , \(x\_2=...\) ;
\(x^2+7x-8=(...)(...)\) .
г) \(\dfrac{x^2-6x+5}{x^2-4x-5}=\dfrac{(...)(...)}{(...)(...)}=...\) ;
\(x^2-6x+5=0\) , \(x\_1=...\) , \(x\_2=...\) ;
\(x^2-4x-5=0\) , \(x\_1=...\) , \(x\_2=...\) .
д) \(\dfrac{4-x^2}{x^2+7x-18}=-\dfrac{x^2-4}{x^2+7x-18}=...\) .
е) \(\dfrac{-12+7x-x^2}{3+2x-x^2}=\dfrac{-(x^2-7x-...)}{-(x^2...)}=...\) .