Соедини части \displaystyle\int _{\pi/3}^{\pi/2}\dfrac{1}{\sin ^2x}dx= \displaystyle\int _{0}^{\pi/4}\dfrac{1}{\cos ^2x}dx= 1 \dfrac{\sqrt{3}}{3}

Задание

Соедини части

\(\displaystyle\int _{\pi/3}^{\pi/2}\dfrac{1}{\sin ^2x}dx=\)	\(1\)
\(\displaystyle\int _{0}^{\pi/4}\dfrac{1}{\cos ^2x}dx=\)	\(\dfrac{\sqrt{3}}{3}\)