Решите уравнение: \(\large2\cos^2{x}-2\sin{2x}+1=0\) \(\large\mathtt{x=\frac{\pi}{4}+\pi{n}, n\in{Z}; x=\arctg{3}+\pi{n}, n\in{Z}}\) \(\large\mathtt{x=\pm\frac{\pi}{4}+\pi{n}, n\in{Z}; x=\arctg{3}+\pi{n}, n\in{Z}}\) \(\large\mathtt{x=\frac{\pi}{4}+2\pi{n}, n\in{Z}; x=\arctg{3}+2\pi{n}, n\in{Z}}\)

Задание

Решите уравнение: \(\large2\cos^2{x}-2\sin{2x}+1=0\)

\(\large\mathtt{x=\frac{\pi}{4}+\pi{n}, n\in{Z}; x=\arctg{3}+\pi{n}, n\in{Z}}\)
\(\large\mathtt{x=\pm\frac{\pi}{4}+\pi{n}, n\in{Z}; x=\arctg{3}+\pi{n}, n\in{Z}}\)
\(\large\mathtt{x=\frac{\pi}{4}+2\pi{n}, n\in{Z}; x=\arctg{3}+2\pi{n}, n\in{Z}}\)