Решите уравнение и найдите корни: \(2cos^2 2x-3=sin2x(1-2sin2x).\) \(-\frac{\pi}{4}+{\pi}k\) \(\frac{\pi}{4}+{\pi}k\) \(-\frac{\pi}{4}+2{\pi}k\) \(\frac{\pi}{4}+2{\pi}k\) \(\frac{3\pi}{4}+2{\pi}k\)

Задание

Решите уравнение и найдите корни: \(2cos^2 2x-3=sin2x(1-2sin2x).\)

\(-\frac{\pi}{4}+{\pi}k\)
\(\frac{\pi}{4}+{\pi}k\)
\(-\frac{\pi}{4}+2{\pi}k\)
\(\frac{\pi}{4}+2{\pi}k\)
\(\frac{3\pi}{4}+2{\pi}k\)