Решите уравнение: \(\cos(2x+\frac{\pi}{4})=1\) .
\(x=-\frac{\pi}{8}+\pi n, n\in \mathbb{Z}\)
\(x=2\pi n, n\in \mathbb{Z}\)
\(x=-\frac{\pi}{4}+2\pi n, n\in \mathbb{Z}\)
\(x=-\frac{\pi}{2}+\pi n, n\in \mathbb{Z}\)